# Quick algebra question. thanks?

Write the equation of a line that contains zero slope, and contains the point (0,-6)

thanks

Relevance

y = -6

• Zero slope means the line is horizontal. Horizontal lines are made up of points that all have the same y value. In your case, every point on the line has a y value of -6. Thus, the equation of the line is y = -6

• y = mx + b

where m is slope (in this case 0) and b is the y-intercept (where the line crosses the y axis)

so it would be

y = 0 * x + (-6)

or y = -6

• This is a horizontal line

y = - 6

• Hi, ANSWER: x=[(-1± √(7)i]/2 How to do it: You must either use the quadratic formula or complete the square. Let’s use the quadratic formula, which is this: x=[-b±√(b²-4ac)]/2a x²+x=-2 x²+x+2=0 So, a=1, b=1, c=2 x=[-1±√(1²-4(1)2)/(2(1)) x=[-1±√(1-8)]/2 x=[-1±√(-7)]/2 x=[-1±√(7)i]/2 Remember that to take the square root of a negative number, take the square root of the number an place and “i” for imaginary outside the radical sign. Hope this helps. FE

• Anonymous

y=mx+b

-6=0(0)+b

-6=b

so, y=mx+b

y=0x-6

or just

y=-6

which means that this is a horizontal line..

and by the way...instead of making this whole noises

anyline that has a slope of 0 is a horizontal line ;)

GOOD LUCK

• y=-6 on a horizontal line

Source(s): my mind!!!!
• a standard form for writing equations is y = mx + b, m= slope.