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# Physics momentum question?

A 58 kg ice skater traveling at 3.2 m/s to the north suddenly grabs the hand of a 61 kg skater traveling at 10.1 m/s in the opposite direction as they pass. The two skaters continue skating together with joined hands. What is the final velocity of the two skaters?

no idea how to do this..

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- Anonymous1 decade agoFavorite Answer
initial momentum = final momentum

m1vi + m2v2 = (m1+m2)v2

v2 = (m1vi + m2v2)/(m1+m2)

v2 = [58(3.2) - 61(10.1)] / [58+61]

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