Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 decade ago

ALGEBRA!! Help please!!!(:?

-4(3-6d)=9(2d-2)

2y+18=12-6(y+7)

8(m-5)=2(3m-8)

6(5k-8)-20=11(2k-3)+3k)

3 Answers

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  • Anonymous
    1 decade ago
    Favorite Answer

    If you want to solve the equations you need to do this:

    First make the product

    -4(3-6d)=9(2d-2)

    -12+24d=18d-18 now you put the "d" whit the "d" and numbers with numbers.

    24d-18d=-18+12 you do the operation

    6d=-6 then you divide

    d=6/6

    d=1

    An the same for the next one. If you need ore help just put me a post that say you need more help.

  • Anonymous
    1 decade ago

    -4(3-6d)=9(2d-2)

    -12+24d=18d-18

    -12+24d=18d-18

    -18d -18d

    -12+6d=18

    +12 +12

    6d=30

    ---- ----

    6 6

    d=5

  • 1 decade ago

    i cannot answer this (sorry!!) but i do know of a good book. Its called painless Algebra and its just easy cliff notes and it has helped by quite a bit on my homework

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