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# Algebra 1 problems ?

The cost of a school banquet is $70 plus $15 per person attending. Determine the linear equation that models this problem. What is the cost for 44 people?

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- 1 decade agoFavorite Answer
x = number of people attending minus 1.

y = total cost

y = 70 + 15x

Cost of the first person + 15 times the number of additional people

- 1 decade ago
15x+70. This is because the number of people will vary, so you know it goes with the x. The 70 is the initial cost that's always there. So for 44 people, do 15(44)+70 and that's it.

- Anonymous1 decade ago
C = total cost

C = 70 + 15x

plug 44 into x and solve...

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- kevin......Lv 41 decade ago
liner equation would be T=15p+70

T is the total and p is the people

so 44 people would cost 730

- Anonymous1 decade ago
70 + 15 * 44 = YOU DO IT. I have a head ache. :(

- 1 decade ago
ok so y=15x+70

15 multiplied by 44 =660 + 70

730

Source(s): this is the kind of stuff in doing in Algebra :]

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