Algebra 1 problems ?

The cost of a school banquet is $70 plus $15 per person attending. Determine the linear equation that models this problem. What is the cost for 44 people?

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  • 1 decade ago
    Favorite Answer

    x = number of people attending minus 1.

    y = total cost

    y = 70 + 15x

    Cost of the first person + 15 times the number of additional people

  • 1 decade ago

    15x+70. This is because the number of people will vary, so you know it goes with the x. The 70 is the initial cost that's always there. So for 44 people, do 15(44)+70 and that's it.

  • 1 decade ago

    =70+15t

    =70+15(44)

    =70+660

    =$730

    the cost would be $730

  • Anonymous
    1 decade ago

    C = total cost

    C = 70 + 15x

    plug 44 into x and solve...

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  • 1 decade ago

    wow wicked simple

    15x+70=cost

    $730 for 44 people

  • 1 decade ago

    liner equation would be T=15p+70

    T is the total and p is the people

    so 44 people would cost 730

  • GREG B
    Lv 5
    1 decade ago

    Ax +bY-C=0

    15X+70-C=0

    15(44)+70-C=0

    660+70=C

    Total cost= 730

  • 1 decade ago

    Equation: 15x + 70

    15(44) + 70 = $730 << ANSWER

  • Anonymous
    1 decade ago

    70 + 15 * 44 = YOU DO IT. I have a head ache. :(

  • 1 decade ago

    ok so y=15x+70

    15 multiplied by 44 =660 + 70

    730

    Source(s): this is the kind of stuff in doing in Algebra :]
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