2x^2+x-6 what is the answer to group this question?

Grouping question

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  • j g
    Lv 5
    1 decade ago
    Favorite Answer

    If you want to factor this question by grouping, multiply the 2 from the x² term with the -6 to get -12. You want factors of -12 which will add to 1(the coefficient of x). The factors of -12 which add to 1 are 4 and -3. Now rewrite your problem into the following:

    2x² + 4x - 3x - 6

    Now group them two at a time:

    (2x² + 4x) + (-3x - 6)

    Now factor each:

    2x(x + 2) -3(x + 2)

    This then simplfies to:

    (x + 2)(2x - 3)

    This is how it factors. You didn't say to solve, so this is where you stop.

    Good luck!

  • 1 decade ago

    to factor by grouping:

    split the middle term into two terms with coefficients that have a product of (2 * -6) = -12 and a sum of 1

    how about 4 * -3

    so 2x^2 + x - 6 = 2x^2 + 4x - 3x - 6

    now factor by grouping in pairs

    (2x^2 + 4x) - (3x + 6)

    take out a gcf in each pair:

    2x(x + 2) - 3(x + 2)

    look at the common factor here: (x + 2)

    (x + 2)(2x - 3)

    hey spider monkey: I don't see an "= 0" here, so it's not an equation, just an expression to factor

  • 1 decade ago

    2x^2+x-6

    (2x-3)(x+2) x=3/2 -2

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