# 2x^2+x-6 what is the answer to group this question?

Grouping question

Relevance

If you want to factor this question by grouping, multiply the 2 from the x² term with the -6 to get -12. You want factors of -12 which will add to 1(the coefficient of x). The factors of -12 which add to 1 are 4 and -3. Now rewrite your problem into the following:

2x² + 4x - 3x - 6

Now group them two at a time:

(2x² + 4x) + (-3x - 6)

Now factor each:

2x(x + 2) -3(x + 2)

This then simplfies to:

(x + 2)(2x - 3)

This is how it factors. You didn't say to solve, so this is where you stop.

Good luck!

• to factor by grouping:

split the middle term into two terms with coefficients that have a product of (2 * -6) = -12 and a sum of 1

so 2x^2 + x - 6 = 2x^2 + 4x - 3x - 6

now factor by grouping in pairs

(2x^2 + 4x) - (3x + 6)

take out a gcf in each pair:

2x(x + 2) - 3(x + 2)

look at the common factor here: (x + 2)

(x + 2)(2x - 3)

hey spider monkey: I don't see an "= 0" here, so it's not an equation, just an expression to factor

• 2x^2+x-6

(2x-3)(x+2) x=3/2 -2