Reduction of Copper from Copper Oxide...help?
Reduction of Copper from Copper Oxide
If you have the following balanced equation which shows the reduction of copper from copper oxide, what is the number of grams of Cu that can be obtained if you have 643.5 grams of copper(II) oxide and 38.0 grams of hydrogen?
H2(g) + CuO(s) --> Cu(s) + H2O(g)
- Dr.ALv 71 decade agoFavorite Answer
moles copper oxide = 643.5 g / 79.5454 g/mol= 8.09
moles H2 = 38.0 g/2.016 g/mol = 18.8 ( in excess)
we get 8.09 moles Cu => 8.09 x 63.546 g/mol= 514.1 g