Reduction of Copper from Copper Oxide...help?

Reduction of Copper from Copper Oxide

If you have the following balanced equation which shows the reduction of copper from copper oxide, what is the number of grams of Cu that can be obtained if you have 643.5 grams of copper(II) oxide and 38.0 grams of hydrogen?

H2(g) + CuO(s) --> Cu(s) + H2O(g)

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  • Dr.A
    Lv 7
    1 decade ago
    Favorite Answer

    moles copper oxide = 643.5 g / 79.5454 g/mol= 8.09

    moles H2 = 38.0 g/2.016 g/mol = 18.8 ( in excess)

    we get 8.09 moles Cu => 8.09 x 63.546 g/mol= 514.1 g

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