A projectile is launched from the ground at an initial velocity,v, and at an angle of θ.?
Determine value of θ that would give the maximum range of the projectile. Also, determine the maximum range in terms of g and v.
- Anonymous1 decade agoFavorite Answer
Theta = 45 degrees
Xmax = vsin(2theta)/g
- dalmasLv 44 years ago
the vertical ingredient to velocity is 60 x sin30 =30 m/s at max ht this velocity is going to 0 substituting in v^2 = u^2 - 2gh 0 = 30 x 30 - 2 x 9.8 x H H = 30 x 30 / 2 x 9.8 = 46m