# complex number division ?

in complex number division is: (2+2j) / (1+j) = 2 ?

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• Anonymous

Multiply by (1-j)/(1-j) to rationalise the denominator and get (2+2j)(1-j)/(1+j)(1-j). As the denominator is the difference of two squares, the js cancel to make (2+2j)(1-j)/1+1. (Expand the brackets and cancel. (j^2 = -1).

Expand the numerator brackets: 2-2j^2 = 2+2.

=> 2+2/1+1 = 4/2 = 2.

• Aslan
Lv 6

factorise the denominator to get 2 + 2j = 2(1+j)

then it becomes clear that you can divide the (1+j) by the (1+j) to give 2 = 2

qed

if ur try ing to solve it

J=2 because 2+2J is really 2+2=4 then 4 divided by 2 =2

So J=2

j is definitely 1 because then it is 4 divided by 2 which equals 2!