calcualting specific heat capcity and percentage error?

from an experiment i found that the specific heat capacity of aluminium is 540000J/KG C

and the actual value is 900J/KG C

i want to calculate the percentage error need help

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  • Anonymous
    1 decade ago
    Favorite Answer

    ((540000-900)/540000)*100=99.83333% difference.

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  • 3 years ago

    Mass of steel(Mm)=27.0. .Temperature of steel(Tm)=18.4. .Mass of water(Mw)=70. .Temperature of water(Tw)=seventy 9.5. .very final temperature of water(Tf)=very final temperature of steel(Tf)=seventy six.8. .particular warmth skill of water(Cw)=4.184. .particular warmth skill of steel(Cm)=?................................ ........................................... ........................................... ........................................... on your arithmetic. .resolve for Cm. .it particularly is your answer. .and remember your unit. .J/g ok

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