Help with this precal problem?

LOGbaseY + LOG(Y+9) = 1

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  • 1 decade ago
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    I'll read this as Log Y + Log (Y+9) = 1

    Log (Y^2 + 9Y) = 1

    Y^2 + 9Y = 10

    (Y+10)(Y-1) = 0

    So Y=-10 or Y=1

    But argument of a log has to be positive....so Y=1.

  • 1 decade ago

    =log y(y+9) =1

    10 = y(y+9)

    10 =y^2 +9y

    y^2 +9y -10=0

    (y+10)(y-1) =0

    y =-10 reject

    y=1

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