# Slope Intercept HELP!!!!?

How would you do these and whats the answers? Thanks

(1). The line has a slope of -2 and passes through point (-2,4). What is its slope intercept?

(2)If a line has a slope of -2, a line perpendicular would have a slope of what?

Thank You

Update:

(3) A vertical line passes through points (-6,3) What is the slope intercept?

Update 2:

OMG Like thankyou everyone! : ) i like so totally forgot how to do these.....Thanx

Relevance

the slope intercept formula is y=mx+b. m is the slope b is the y intercept. So your formula would be

y=-2/1x + 4 To solve for y, put a 0 in for x. To solve for x, put a 0 in for y.

A perpendicular line always has a slope that is the negative reciprocal of the other line. If 1 line has a slope of -2, a perpendicular line would have a slope of 1/2

A line can be written in the form of y=mx+b where m=slope b=y-intercept

1) y=mx+b so y=-2x+b we have a point that we can use to find b, we have (x, y)=(-2, 4) as a point so plug in the numbers and find b. 4=-2(-2)+b

4=4+b so b=0 and y=-2x+0=-2x

2) The slope of the perpendicular line is the negative reciprocal of the slope of the given line, this means you flip it and multiply by -1 so -2=-2/1, slip it and you get 1/-2=-1/2, multiply this by -1 and you get 1/2=slope of perpendicular line

3) Vertical means it goes straight up so y is changing but x is always the same which means x is always -6 so the equation is x=-6.

1)

the slope-intercept form is y=mx+b

m=the slope

b=the y intercept

x and y = point/coordinates

What you do is you substitute in -2 for m, -2 for x, and 4 for y and solve it algebraicly

2) *Hint- the slope of a perpendicular line is the negative reciprocal

If you can't solve it on your own: the answer is 1/2 because the reciprocal is when you swap the numerator and the denominator and then you multiply it by -1

3) the line goes straight up and the slope is rise/run so it is the number/0 making the slope 0.

just do what you did in number one and substitute 0 for m and -6 for x and 3 for y and solve it algebraically

Source(s): I'm in Honors Geometry
• Dee W
Lv 7

1. y = mx + b

4 = -2(-2) + b

4 = 4 + b

0 = b

y = -2x

2. perpendicular line slope would be 2/1 or 2

• Anonymous

y = mx + b

m = slope

y = the second part of the numbers in parentheses

x = the first part

b = the intercept

So plug in the values of x, y, and m into y = mx + b.

4 = 2(-2) + b.

Solve for b.

4 = -4 + b

8 = b

The perpendicular of a slope is the inverse reciprocal of the slope. Reciprocal of n is 1/n. So perpendicular of -2 = 1/(-2) = -1/2.

• Anonymous

ok,nubah uno.

so y=mx+b

(-2,4) is (x,y)

m is slope so -2.

alright. b is the slope intercept, plug and chug!

4=-2(-2)+b

4=4+b

-4 -4

0=b that is number one.

Numbah two.

a perpendicular line is a opposite reciprocal.

-2 (flip) 1/-2 (and *-1) 1/2

that is you new slope.

numbah 3

vertical lines are up and down, slope is rise over run.

therefore, you have no run aka it is zero.

rise over zero is always undefined.

hope it helps!

1. Slope intercept form is y=mx+b

Plug the point and the slope into the point slope form

y-y1=m(x-x1)

y-4=-2(x+2)

then solve for y

y=-2x

2. Flip and negate your slope for a perpendicular line. so it would be 1/2

1) put it slope intercept form...y=mx+b

m is the slope, b is the y intercept, x is -2 and y is 4

2) the slope would be 1/2(the opposite reciprocal of the slope, -2

i hope this helps!

Source(s): my brain