# Slope Intercept HELP!!!!?

How would you do these and whats the answers? Thanks

(1). The line has a slope of -2 and passes through point (-2,4). What is its slope intercept?

(2)If a line has a slope of -2, a line perpendicular would have a slope of what?

Thank You

Update:

(3) A vertical line passes through points (-6,3) What is the slope intercept?

Update 2:

OMG Like thankyou everyone! : ) i like so totally forgot how to do these.....Thanx

Relevance

the slope intercept formula is y=mx+b. m is the slope b is the y intercept. So your formula would be

y=-2/1x + 4 To solve for y, put a 0 in for x. To solve for x, put a 0 in for y.

A perpendicular line always has a slope that is the negative reciprocal of the other line. If 1 line has a slope of -2, a perpendicular line would have a slope of 1/2

• A line can be written in the form of y=mx+b where m=slope b=y-intercept

1) y=mx+b so y=-2x+b we have a point that we can use to find b, we have (x, y)=(-2, 4) as a point so plug in the numbers and find b. 4=-2(-2)+b

4=4+b so b=0 and y=-2x+0=-2x

2) The slope of the perpendicular line is the negative reciprocal of the slope of the given line, this means you flip it and multiply by -1 so -2=-2/1, slip it and you get 1/-2=-1/2, multiply this by -1 and you get 1/2=slope of perpendicular line

3) Vertical means it goes straight up so y is changing but x is always the same which means x is always -6 so the equation is x=-6.

• 1)

the slope-intercept form is y=mx+b

m=the slope

b=the y intercept

x and y = point/coordinates

What you do is you substitute in -2 for m, -2 for x, and 4 for y and solve it algebraicly

2) *Hint- the slope of a perpendicular line is the negative reciprocal

If you can't solve it on your own: the answer is 1/2 because the reciprocal is when you swap the numerator and the denominator and then you multiply it by -1

3) the line goes straight up and the slope is rise/run so it is the number/0 making the slope 0.

just do what you did in number one and substitute 0 for m and -6 for x and 3 for y and solve it algebraically

Source(s): I'm in Honors Geometry
• 1. y = mx + b

4 = -2(-2) + b

4 = 4 + b

0 = b

y = -2x

2. perpendicular line slope would be 2/1 or 2

• Anonymous

y = mx + b

m = slope

y = the second part of the numbers in parentheses

x = the first part

b = the intercept

So plug in the values of x, y, and m into y = mx + b.

4 = 2(-2) + b.

Solve for b.

4 = -4 + b

8 = b

The perpendicular of a slope is the inverse reciprocal of the slope. Reciprocal of n is 1/n. So perpendicular of -2 = 1/(-2) = -1/2.

• Anonymous

ok,nubah uno.

so y=mx+b

(-2,4) is (x,y)

m is slope so -2.

alright. b is the slope intercept, plug and chug!

4=-2(-2)+b

4=4+b

-4 -4

0=b that is number one.

Numbah two.

a perpendicular line is a opposite reciprocal.

-2 (flip) 1/-2 (and *-1) 1/2

that is you new slope.

numbah 3

vertical lines are up and down, slope is rise over run.

therefore, you have no run aka it is zero.

rise over zero is always undefined.

hope it helps!

• 1. Slope intercept form is y=mx+b

Plug the point and the slope into the point slope form

y-y1=m(x-x1)

y-4=-2(x+2)

then solve for y

y=-2x

2. Flip and negate your slope for a perpendicular line. so it would be 1/2

• 1) put it slope intercept form...y=mx+b

m is the slope, b is the y intercept, x is -2 and y is 4

2) the slope would be 1/2(the opposite reciprocal of the slope, -2

i hope this helps!

Source(s): my brain
• 1. I forgot how to do those.

2. Positive 1/2

• Anonymous