X  y= 4 , 2x + y= 5 solve linear equations and express in ordered pairs?
Follow
 ✓Follow publicly
 ✓Follow privately
 Unfollow
Is system independent, inconsistent or dependent? Please show algebraic steps used to get this answer.
Best AnswerAsker's Choice
To find the ordered pair, you use either substitution or you can combine the equations. I think substitution's more fun, so I'll do that.
xy=4 > y=x4
2x+y=5 > 2x+x4=5 > 3x=9 > x=3
y=x4 > y=34 > y=1
The ordered pair is, therefore, (3,1). You can check this if you want by plugging the numbers back into the original equations.
Because the lines for y=x4 and y=52x are not parallel and intersect at one point, the system is independent.
xy=4 > y=x4
2x+y=5 > 2x+x4=5 > 3x=9 > x=3
y=x4 > y=34 > y=1
The ordered pair is, therefore, (3,1). You can check this if you want by plugging the numbers back into the original equations.
Because the lines for y=x4 and y=52x are not parallel and intersect at one point, the system is independent.
Source:
Other Answers (6)
Rated Highest
when xy=4
And 2x+y=5
x=4+y
then 2( 4+y ) + y=5
8+2y+y=5 & 3y=58 then 3y=3
Y = 1
x  ( 1 ) =4 & x+1=4
X = 3 
x  y = 4
2x + y = 5
¯¯¯¯¯¯¯¯¯¯¯
 x =  1 (Subtract second equation from first)
x = 1
1  y = 4 (Substitute 1 for y)
 y = 4  1
 y = 3
y =  3
Ordered Pair (1,  3)
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

x=3 y= 1
independent
1x  1y = 4
2x + 1y = 5

3x + 0y = 9
x = 3
y=1

2x+y=5 ; xy=4
2(3)+(1)=5 (3)(1)=4
61=5 3+1=4
x=3 ; y= 1
not sure. XD
Source(s):
http://www.algebra.com/algebra/homework/coordinate/lessons/Typesofsystemsinconsistentdependentindependent.lesson 
x=3 y= 1
independent
1x  1y = 4
2x + 1y = 5

3x + 0y = 9
x = 3
y=1 
x  y = 4 (EQ1)
2x + y = 5 (EQ2)
Solve EQ1 for x:
x = y + 4
Substitute this value into EQ2:
2(y + 4) + y = 5
Solve for y:
2y + 8 + y = 5
3y = 3
y = 1
Plug into EQ1 and solve for x:
x  (1) = 4
x + 1 = 4
x = 3
Solution:
(3, 1)
Dependent
Sign In
to add your answer