Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and the Yahoo Answers website is now in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

acceleration, 0 to 669,600,000 MPH at 1G?

i would like to know the time it would take to go from zero to the speed of light (186,000 MPS) at one steady G force. Or where to look for the answer?

2 Answers

Relevance
  • 1 decade ago
    Favorite Answer

    Since our initial velocity is 0, our equation is

    v = gt

    where v is velocity, g is acceleration, and t is time. Hence,

    t = v/g

    Since g is 32 feet/sec/sec, let's convert light speed to feet/sec.

    (186,000 miles/sec)(5280 feet/mile) = 982080000 feet/sec

    So the time in seconds will be (982080000 feet/sec)/(32 feet/sec/sec)

    = 30690000 sec

    Divide by 3600 sec/hour to get hours,

    = 8525 hours

    Divide by 24 hours/day to get days,

    = 355.2083 days

    So it would take nearly a year!

  • Andy J
    Lv 7
    1 decade ago

    One G is 9.81 m/s². Just divide into the speed of light (299,792,458 m/s) to get:

    299,792,458 m/s / 9.81 m/s² = 30,559,883 s

    That's 353.7 days.

Still have questions? Get your answers by asking now.