Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and the Yahoo Answers website is now in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
acceleration, 0 to 669,600,000 MPH at 1G?
i would like to know the time it would take to go from zero to the speed of light (186,000 MPS) at one steady G force. Or where to look for the answer?
- statmanLv 61 decade agoFavorite Answer
Since our initial velocity is 0, our equation is
v = gt
where v is velocity, g is acceleration, and t is time. Hence,
t = v/g
Since g is 32 feet/sec/sec, let's convert light speed to feet/sec.
(186,000 miles/sec)(5280 feet/mile) = 982080000 feet/sec
So the time in seconds will be (982080000 feet/sec)/(32 feet/sec/sec)
= 30690000 sec
Divide by 3600 sec/hour to get hours,
= 8525 hours
Divide by 24 hours/day to get days,
= 355.2083 days
So it would take nearly a year!
- Andy JLv 71 decade ago
One G is 9.81 m/s². Just divide into the speed of light (299,792,458 m/s) to get:
299,792,458 m/s / 9.81 m/s² = 30,559,883 s
That's 353.7 days.