i have two geometry question 10 grade?

there is a diagram of two lines that look like they are perpendicular line CED and AEB. This is a proof and the given is that CED and AEB intersect at E and angle AEC is congruent to angle CEB, prove that line AEB and CED are perpendicular.

The next one shows a triangle it is labeled B at the top A at the left bottom side and C at the right bottom side and there is a line that starts at B and goes to the line AB that point is D. The given is that angle ABC is a a right angle and angle BAC complementary to angle DBA. Prove angle BAC is congruent to angle CBD

if you can understand any of this please help

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  • 1 decade ago
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    there is a diagram of two lines that look like they are perpendicular line CED and AEB. This is a proof and the given is that CED and AEB intersect at E and angle AEC is congruent to angle CEB, prove that line AEB and CED are perpendicular.

    >>AEC and CEB are supplementary because they have shared side EC and AEB is a straight line (which is the same as a "straight angle" -- an angle of 180 degrees), so mAEC + mCEB = 180 degrees. (The m means "the measure of".)

    >>mAEC = mCEB (Given.)

    >>mAEC + mCEB = 180, so they must both be 90 degrees. (180/2)

    The next one shows a triangle it is labeled B at the top A at the left bottom side and C at the right bottom side and there is a line that starts at B and goes to the line AB that point is D. The given is that angle ABC is a a right angle and angle BAC complementary to angle DBA. Prove angle BAC is congruent to angle CBD

    >>Do you havw a typo in this one? Something doesn't quite make sense...

    Hope this helps!

    barjesse37

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