請問水產品細菌有哪些

Foods high in unsaturated fats produce oleic acid which is transformed into a compound called oleoylethanolamide (OEA) in the small intestines. OEA suppresses appetite by sending messages to the brain that lead to feelings of fullness. Previous studies have shown that when OEA levels are increased, it promotes weight loss and even lowers blood cholesterol and triglyceride levels.

設一工廠製造玻璃每100平方工尺有依各氣泡瑕疵.今購買該工廠的依片10呎寬30呎長的玻璃.是求

1沒有氣泡瑕疵的機率

2恰有兩各氣泡瑕疵的機率

三、According to a report issued by the Food and Drug Association (FDA) of US, total protein consumed per day by adults of age between 18 to 30 years are approximately normally distributed with a mean of 150mg and a standard deviation of 20mg.

1. Find the probability that an adult picked at random will consume more than 200mg protein a day.

2. If 2,000 adults were chosen randomly, how many of them would you expect to have consumed 120 to 180mg protein a day?

3. Calculate Q1, Q3 of the daily consumed protein level

Foods high in unsaturated fats produce oleic acid which is transformed into a compound called oleoylethanolamide (OEA) in the small intestines. OEA suppresses appetite by sending messages to the brain that lead to feelings of fullness. Previous studies have shown that when OEA levels are increased, it promotes weight loss and even lowers blood cholesterol and triglyceride levels.

1 Answer

Rating
  • 1 decade ago
    Favorite Answer

    平均每100平方公尺有一個氣泡瑕疵,換句話說,300平方公尺(10 × 30 = 300)有三個氣泡瑕疵(λ = 3)。

          (e^-λ)×(λ^x)

    公式:f(x) = ---------------------,x = 0,1,2,…

             x!

    1.

    P(沒有氣泡瑕疵)

    = P(X = 0)

      (e^-3)×(3^0)

    = -------------------------

          0!

    = 0.04979

    2.

    P(恰有兩各氣泡瑕疵)

    = P(X = 2)

      (e^-3)×(3^2)

    = -------------------------

         2!

    = 0.22404

    2008-10-23 23:09:41 補充:

    Xi~N( 150,20² )

    1. P( X > 200)

         200 - 150

     = P( Z < ----------------- )

           20

     = P( Z < 2.5 )

     = 0.9973

    2008-10-23 23:10:07 補充:

    2. P( 120 < X < 180)

     = P( X < 180 ) - P( X < 120)

         180 - 150      120 - 150

     = P( Z < ----------------- ) - P( Z < ----------------- )

          20         20

     = P( Z < 1.5 ) - P( Z < -1.5 )

     = 0.9332 - 0.0668

     = 0.8664

    2008-10-23 23:10:15 補充:

     2000 × 0.8664 = 1732.7712

     So, there are 1,733 adults have consumed 120 to 180mg protein a day.

    2008-10-23 23:10:33 補充:

    3. P( X < Q1)

         Q1 - 150

     = P( Z < --------------- )

          20

     = P( Z < -0.6745 )

     = 0.25

     Q1 = 150 + 20 × -0.6745 = 136.51

     Q1 of the daily consumed protein level is 136.51mg.

    2008-10-23 23:10:47 補充:

     P( X < Q3)

         Q1 - 150

     = P( Z < ---------------- )

          20

     = P( Z < 0.6745 )

     = 0.75

     Q3 = 150 + 20 × 0.6745 = 163.49

     Q3 of the daily consumed protein level is 136.51mg.

    Source(s): 我的求學過程…
Still have questions? Get your answers by asking now.