Joy asked in Science & MathematicsBiology · 1 decade ago

Suppose 64% of a remote mountain village can taste phenylthiocabamide (PTC) and must therefore have at least o?

Update:

*one copy of the dominant PTC taster allele. If this population conforms to Hardy-Weinberg expectations for this gene, what percentage of the population must be heterozygous for this trait?

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  • 1 decade ago
    Best Answer

    If 64% can, 36% can't. (100% - 64% = 36%)

    q^2 = 0.36

    q = 0.6.

    p = 1 - 0.6 = 0.4

    Heterozygotes = 2pq = 2 (0.4) (0.6) = .48

    48% of the population.

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