solve for r...10 easy points!!!!?

r^2+3r=2 The solutions are r=????

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  • 1 decade ago
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    r^2+3r-2 = 0

    Factorize the equation. then

    (r+1)(r-3) = 0

    Therefore, r = -1 & 3

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  • 1 decade ago

    r^2+3r=2 => r^2+3r-2=0 => (r+1) (r-3)=0 =>r=3 & -1

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  • 1 decade ago

    r^2 + 3r - 2 = 0

    for any quadratic equation of the form

    ax^2 +bx + c =0

    x = -b +- sqrt (b^2 - 4 * a * c)

    ------------------------------------------

    2 * a

    Solving this, by the above formula, we get

    r = -3 +- sqrt (9-4*1*-2)

    ------------------------------------

    2

    = [-3 +- sqrt (17)]/2

    =[ -3 +- 4.12]/2

    = -7.12/2 or 1.12/2

    =- 3.56 and 0.56

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