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# chain rule

y=sin(cos(tan(3x+1))

find dy/dx by using chain rule

Update:

please use chain rule...

### 1 Answer

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- wyLv 71 decade agoFavorite Answer
dy/dx = d[sin(cos(tan(3x +1)))]/d[cos(tan(3x+1))] times d[cos(tan(3x+1))]/d[tan(3x +1)] times d[tan(3x+1)]/d(3x+1) times d(3x +1)/dx

= cos(cos(tan(3x+1)) times -sin(tan(3x+1)) times sec^2(3x+1) times 3

= -3[cos(cos(tan(3x+1)))][sin(tan(3x+1))][sec^2(3x+1)].

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