芷羚 asked in 社會及文化語言 · 1 decade ago

There are x sweets in a box.

There are x sweets in a box.If 3are taken away and the remaining are duvied to6 children,each child will get less 7sweets.

a)Set up an inequality for x.

b)Would the number of steews be 51?

c)Would the number of steews be 39?

1 Answer

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  • 1 decade ago
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    a) (x-3)/6 <7

    b) let x be 51

    48/6

    8 is not <7 so the number of sweets would not be 51

    c) 36/6

    =6

    because 6 <7 , the number of sweets would be 39

    Source(s): ~
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