In the equilibrium Ca(oH)2__Ca^2++2OH^-,?
how do the following changes effect the equilibrium:add solid Ca(oH)2, add Ca^2, increase PH, add KCL. thanks
- Dietrich WLv 61 decade agoFavorite Answer
Ca(OH)2<=> Ca2+ + 2 OH-
1) Adding Ca2+:
The right side of the equilibrium is disturbed and forms Ca(OH)2
2) Increasing pH:
OH- is taken out of the system( neutralization of OH-) -> more Ca(OH)2 is soluble. // Shift to the right side of eq.
3) Adding KCl
The K+ would decrease the activity coefficient ( see your thermodynamics textbook) of Ca+ so more Ca2+ goes in to solution. // Shift to the right side