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# What is the height of water, in cm, that can be supported by 1 standard atmosphere of pressure?

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- 1 decade agoFavorite Answer
p = density of water = 1g/mL = 1000kg/L

1 atm = 101.3 kPa = 101.3kN/m^2

Pressure = pgAh/A >(Ah is volume, pAh is mass, pgAh is force)

Pressure = pgh

h = pressure/(pg)

h = (101.3*10^3)/(1000*9.81)

h = 10.33 m

h = 1033 cm

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