find the equation of the circle with a center (-1,-3); passes through (-4,-2)?

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  • Anonymous
    1 decade ago
    Favorite Answer

    ( X + 1 )^2 + (y + 3)^2 =10

  • Lucy
    Lv 7
    1 decade ago

    Circle Equation:

    (x - h)^2 + (y - k)^2 = r^2

    Given: Center (-1, -3)

    Means: (-1, -3) = (h, k)

    Plug these into the formula.

    (x - h)^2 + (y - k)^2 = r^2

    (x - -1)^2 + (y - -3)^2 = r^2

    (x + 1)^2 + (y + 3)^2 = r^2

    Given: passes through (-4, -2)

    Means: (-4, -2) => (x, y)

    Means: distance between this point and the center is r

    Use (-1, -3) for (h, k).

    Use (-4, -2) for (x, y).

    Plug these into the formula.

    r^2 = (x - h)^2 + (y - k)^2

    r^2 = (-4 - -1)^2 + (-2 - -3)^2

    r^2 = (-4 + 1)^2 + (-2 + 3)^2

    r^2 = (1)^2 + (-3)^2

    r^2 = 1 + 9

    r^2 = 10

    Plug this into the formula.

    (x + 1)^2 + (y + 3)^2 = r^2

    (x + 1)^2 + (y + 3)^2 = 10

  • Como
    Lv 7
    1 decade ago

    r² = (- 4 + 1)² + (- 2 + 3)²

    r² = 9 + 1

    r² = 10

    (x + 1)² + (y + 3)² = 10

  • 1 decade ago

    (X+1)^2 + (Y-3)^2=R^2,R^2=(-4+1)^2 +(-2-3)^2=25+25=50

    (Y-3)^2 + (X+1)^2=50

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  • Anonymous
    1 decade ago

    h

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