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# find the equation of the circle with a center (-1,-3); passes through (-4,-2)?

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- Anonymous1 decade agoFavorite Answer
( X + 1 )^2 + (y + 3)^2 =10

- LucyLv 71 decade ago
Circle Equation:

(x - h)^2 + (y - k)^2 = r^2

Given: Center (-1, -3)

Means: (-1, -3) = (h, k)

Plug these into the formula.

(x - h)^2 + (y - k)^2 = r^2

(x - -1)^2 + (y - -3)^2 = r^2

(x + 1)^2 + (y + 3)^2 = r^2

Given: passes through (-4, -2)

Means: (-4, -2) => (x, y)

Means: distance between this point and the center is r

Use (-1, -3) for (h, k).

Use (-4, -2) for (x, y).

Plug these into the formula.

r^2 = (x - h)^2 + (y - k)^2

r^2 = (-4 - -1)^2 + (-2 - -3)^2

r^2 = (-4 + 1)^2 + (-2 + 3)^2

r^2 = (1)^2 + (-3)^2

r^2 = 1 + 9

r^2 = 10

Plug this into the formula.

(x + 1)^2 + (y + 3)^2 = r^2

(x + 1)^2 + (y + 3)^2 = 10

- nozar nazariLv 71 decade ago
(X+1)^2 + (Y-3)^2=R^2,R^2=(-4+1)^2 +(-2-3)^2=25+25=50

(Y-3)^2 + (X+1)^2=50

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- Anonymous1 decade ago
h

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