Please find sinX and cosX given that tanX = 3?

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  • 1 decade ago
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    tan(x) = sin(x)/cos(x)= 3

    sin(x) = 3cos(x)

    sin(x) = 3√[1-sin²(x)]

    let y=sin(x)

    y = 3√(1-y²)

    y² = 9(1-y²)

    y² = 9 - 9y²

    y² = 9/10

    y = ±3/√10

    sinX = 3√10/10

    cosX = √10/10

    or

    sinX = -3√10/10

    cosX = -√10/10

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