Whats '5+3[1+2(2x-3)]=6(x+5)?

solve for x

Update:

and can you please show work

6 Answers

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  • 1 decade ago
    Favorite Answer

    First work inside the parentheses, and distribute.

    5+ 3(1+2(2x-3))=6(x+5)

    5+3((4x-6)+1)=5+3(4x-5)=5+12x-15=12x-10.

    12x-10=6x+30. Next, try to isolate an x on one side. minus 6x+10 on both sides.

    6x=40. Divide by 6.

    x=40/6, or 20/3.

  • 1 decade ago

    5+3[1+2(2x-3)]=6(x+5)

    5+3[1+4x-6]=6(x+5) first step is mult. 2 by (2x-3)

    5+3[4x-5]=6(x+5) add the 1 to the now 4x-6

    5+12x-15=6(x+5) Mult. 4x-6 by 3

    12x-10=6x+30 Add the 5 to -15, so it becomes a -10

    6x-10=30 Subtract 6x from both sides

    6x=40 Add 10 to the other side, so one side will have a variable and the other a reg. number

    x=40/6=20/3 Divide 40 by 6, and when you reduce, you get 20/3..then plug the answer back in as x to check if it's right...if both sides= the same # it's right...if not SOL and try again

    Yay it's right!

    Okay with the calc. or manually

    if you substitute x with 20/3,

    you get 70 on both sides

    = ]

    Always remember PEMDAS (please excuse my dear aunt sally aka parentheses, exponent, multiplication, division, addition, subtraction...the order of operations)

  • Anonymous
    1 decade ago

    5+3[1+2(2x-3)]=6(x+5)

    8[3(2x-3)]=6x+30

    8(6x-9)=6x+30

    48x-72=6x+30

    +72 +72

    48x=6x+102'

    -6x

    42x=102

    divide 42

    x approximately =23.5

    Source(s): my brain
  • 1 decade ago

    5+3+12x-18=6x+30

    6x=40

    x=20/3

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  • 1 decade ago

    5+3[1+2(2x-3)]=6(x+5)

    8[3(-1)=6(x+5)

    24=6(x+5)

    24=6x+30

    -30

    _________

    24=6x+0

    24/6=4

    Source(s): me and my brain and my big sis
  • B
    Lv 4
    1 decade ago

    im assuming its a math prob u got 4 hw? i dunno! sry...

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