## Trending News

Promoted

Anonymous

# Please help me.. Best Answer?

A person exerted a force of 810 N on a 7 kg bowling ball. If the force was extended through a distance of 2 m, how high did the ball go from the point of release?

### 6 Answers

Relevance

- 1 decade agoFavorite Answer
Your throwing a bowling ball vertically upward? Not the optimal way to bowl...

the easiest way to solve your question is to use the energy equations.

The work done on the ball is F.d = 810.2 = 1620 J

At top of flight the kinetic energy is zero, so all the energy is gravitational potential energy.

mgh = 1620 J

h = 1620 / 7 / 9.8

h = 23.6m

But you released th ball 2 metres up, so the ball will continue

23.6 - 2 = 21.6m

Above your head...a bowling ball! RUN!

- Anonymous1 decade ago
it was a gutter ball worth zero points. go for the spare

- How do you think about the answers? You can sign in to vote the answer.
- Anonymous1 decade ago
E=MC2

- Anonymous1 decade ago
this question reminds me of a physics test i failed......

Still have questions? Get your answers by asking now.