A small hole in the wing of a space shuttle requires a 16.2 cm^2 patch. What is the patch's area in square km?

A small hole in the wing of a space shuttle requires a 16.2 cm^2 patch. What is the patch's area in square km?

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  • Anonymous
    1 decade ago
    Favorite Answer

    cm^2 = cm X cm = cm(cm)

    100,000 cm in a km.

    Converting from cm to km:

    16.2 cm^2 X (1 km / 100,000 cm) X (1 km / 100,000 cm).

    Unit analysis shows you now have (cm^2 X km^2) / cm^2 = km^2.

    cm^2 units cancel out.

    The correct answer is 1.62 * 10^-9 km^2.

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  • 1 decade ago

    roughly .176 km^2

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  • 1 decade ago

    1 m=100 cm..or 1 cm=.01m...1 cm^2=(.01)(.01)m^2..and 1 m=10^-3km.. so 1 cm^2=.01x10^-3x.01x10^-3km^2=1x10^-10km^2..so 16.2cm^2=16.2x1x10^-10km^2=1.62x10^-9km^2...done

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  • JB
    Lv 4
    1 decade ago
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