# How do I integrate Cos x Sin x dx?

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How do I integrate Cos x Sin x dx? I'm working on an engineering problem and having trouble getting up to speed with simple integral calculus. Any help is much appreciated!

### Other Answers (5)

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cos(x)*sin(x)=1/2 *sin(2x)=>

int(cosx*sinx*dx)=int(1/2*sin(2x)dx)

=-1/4*cos(2x) -
cosx sinx dx = 1/2sin^2 x +c ,meaning half of sinx square

also cosxsinx = -1/2cos^2 x + c ,means half of cos square negative. -
∫cosx sinx dx

= ∫sinx dsinx

= (1/2)sin^2(x) + c -
since

dy/dx (cos x) = - sin x

dy/dx (sin x) = cos x

then integrating them wld be the opp of it.

integral of Cos x = sin x

Integral of Sin x = - cos x

Integral of Cos x Sin x

= Integral of Cos x + integral of Sin x

= Sin x - cos x -
CosXSinS is as simplified as it gets.

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