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# 3個線型函數,函數問題!! very easy!!

1.Give the slope of the line that contain (-8,-2) and (-2,-2)

2.Write the standard form of the equetion of the line with slope 0 passing

through the point (4,-3)

3.Which of the following lines is not parellelto y = -3x +3

PLEASE HELP ME!!!!!

sorry

3.Which of the following lines is not parellelto y = -3x +3

A y+3x=3

B-3x+y=3

C-3x-y=2

D-6x-2y=2

2.Write the standard form of the equetion of the line with slope 0 passing

through the point (4,-3)

A x=-3

B x=4

C y=-3

Dy=4

HOW CAN I KNOW IT'S 斜率 ?

### 1 Answer

- ?Lv 51 decade agoFavorite Answer
1.-2-(-2)/-2-(-8)=0/6=0所以斜率為0

2.y-(-3)=0*(x-4)+c

y=-3+c

3.因資料不足請補充

(翻譯：下列哪一條線不平行於 y = -3x +3)

2008-08-23 03:58:22 補充：

2.且通過(4.-3)帶入原來等式

得到C=0，因此Y=-3

3.原式斜率為 -3

A.斜率為 -3

B.斜率為 3

C.斜率為 -3

D.鞋率為 -3

所以答案為 B

Y=AX+B A為斜率，依提要求為斜率相異者

2008-08-23 04:41:31 補充：

相互平行的直線，會有相同的斜率，而斜率(m)等於y軸變化量 / x軸變化量

Source(s): 自己