Anonymous
Anonymous asked in 教育與參考其他:教育 · 1 decade ago

3個線型函數,函數問題!! very easy!!

1.Give the slope of the line that contain (-8,-2) and (-2,-2)

2.Write the standard form of the equetion of the line with slope 0 passing

through the point (4,-3)

3.Which of the following lines is not parellelto y = -3x +3

PLEASE HELP ME!!!!!

Update:

sorry

3.Which of the following lines is not parellelto y = -3x +3

A y+3x=3

B-3x+y=3

C-3x-y=2

D-6x-2y=2

Update 2:

2.Write the standard form of the equetion of the line with slope 0 passing

through the point (4,-3)

A x=-3

B x=4

C y=-3

Dy=4

Update 3:

HOW CAN I KNOW IT'S 斜率 ?

1 Answer

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    Lv 5
    1 decade ago
    Favorite Answer

    1.-2-(-2)/-2-(-8)=0/6=0所以斜率為0

    2.y-(-3)=0*(x-4)+c

    y=-3+c

    3.因資料不足請補充

    (翻譯:下列哪一條線不平行於 y = -3x +3)

    2008-08-23 03:58:22 補充:

    2.且通過(4.-3)帶入原來等式

    得到C=0,因此Y=-3

    3.原式斜率為 -3

    A.斜率為 -3

    B.斜率為 3

    C.斜率為 -3

    D.鞋率為 -3

    所以答案為 B

    Y=AX+B A為斜率,依提要求為斜率相異者

    2008-08-23 04:41:31 補充:

    相互平行的直線,會有相同的斜率,而斜率(m)等於y軸變化量 / x軸變化量

    Source(s): 自己
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