Predict the population?
The population of Glenbrook is 375,000 and is increasing at the rate of 2.25% per year. Predict when the population will be 1 million.
- Anonymous1 decade agoFavorite Answer
Population growth problems are usually done by using the exponential equation
P = Po(e^-kt)
P = population at any time "t"
Po = initial population = 375,000 (given)
k = exponential constant = 0.0225 (given)
t = time
Given the above data, the equation is modified to
P = 375,000(e^-0.025t)
And when P = 1,000,000, the above becomes
1,000,000 = 375,000(e^-0.0225t)
2.667 = e^0.0225t
Taking the natural logarithm of both sides,
ln (2.667) = 0.0225t (ln e)
Since ln e = 1 and solving for "t",
t = (1/0.0225)(ln 2.667)
t = 43.6 years
t = 43 years and 7 months ~