# If two cards are drawn without replacement from an ordinary deck, ?

Solve the problem.

If two cards are drawn without replacement from an ordinary deck, find the probability that the second card is an ace, given that the first card was an ace.

a. 4/51

b. 1/17

c. 1/3

d. 3/52

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If the first card was an ace, there are 3 aces left in the deck. Since this occurs without replacement, there are 51 cards remaining. Therefore, the probability of drawing a second ace is 3/51 = 1/17.

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• 3 aces out of 51 cards

3/51 = 1/17

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• there are fifty 2 playing cards in a deck. there are 12 face playing cards interior the deck. because you already drew one face card, there are 11 left. and because that there is not any change you've fifty one playing cards left interior the deck after drawing the first one. hence your answer is 11/fifty one

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• 1/17.

Is this a trick question?

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