Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 decade ago

What is the quadratic coefficient, the linear coefficient, and the constant term for a quadratic function that

has its vertex at the point (5,−2). The function passes through the point (−6,−4

4 Answers

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  • lou h
    Lv 7
    1 decade ago
    Favorite Answer

    y+2= A·(x-5)² --> y= A·(x-5)²-2 with -4=A·(-6-5)²-2 --> A= -2/121

    ==> y= -2/121·(x-5)² - 2 = -2/121·x² + 20/121·x -292/121

    the quadratic coefficient= -2/121

    the linear coefficient= 20/121

    the constant term= -292/121

    Saludos

  • 4 years ago

    Quadratic Coefficient

  • Anonymous
    5 years ago

    For the best answers, search on this site https://shorturl.im/avn9v

    Vertex at (9, -5) => y = a(x - 9)² - 5, for some constant a, which we must find. Passes through (7, 4) => 4 = a(7 - 9)² - 5 = 4a - 5 => a = 9/4. ∴ y = (9/4)(x - 9)² - 5 = (9/4)(x² - 18x + 81) - 5 = (9/4)x² - (81/2)x + 709/4. Quadratic coefficient: 9/4 Linear coefficient: -81/2 Constant term: 709/4

  • 1 decade ago

    y = a.x ^ 2 + b.x + c

    -2 = 25a + 5b + c

    -4 = 36a - 4b + c

    5 = -b / 2a

    use these to find a,b,c

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