## Trending News

# What is the quadratic coefficient, the linear coefficient, and the constant term for a quadratic function that

has its vertex at the point (5,−2). The function passes through the point (−6,−4

### 4 Answers

- lou hLv 71 decade agoFavorite Answer
y+2= A·(x-5)² --> y= A·(x-5)²-2 with -4=A·(-6-5)²-2 --> A= -2/121

==> y= -2/121·(x-5)² - 2 = -2/121·x² + 20/121·x -292/121

the quadratic coefficient= -2/121

the linear coefficient= 20/121

the constant term= -292/121

Saludos

- Anonymous5 years ago
For the best answers, search on this site https://shorturl.im/avn9v

Vertex at (9, -5) => y = a(x - 9)² - 5, for some constant a, which we must find. Passes through (7, 4) => 4 = a(7 - 9)² - 5 = 4a - 5 => a = 9/4. ∴ y = (9/4)(x - 9)² - 5 = (9/4)(x² - 18x + 81) - 5 = (9/4)x² - (81/2)x + 709/4. Quadratic coefficient: 9/4 Linear coefficient: -81/2 Constant term: 709/4

- 1 decade ago
y = a.x ^ 2 + b.x + c

-2 = 25a + 5b + c

-4 = 36a - 4b + c

5 = -b / 2a

use these to find a,b,c