The velocity of an object at time t is given by v(t)=9t^2 8t - 10.
At time t=1, the position of the object is S(1)=1. How many and which ones are true? :
- 1 decade agoFavorite Answer
I also assume v(t) = 9t^(2) + 8t - 10, then you can integrate it (and not differentiate it like Boiler said) to find s(t). I got s(t) = 3t^3 + 4t^2 - 10t + C
then you use your the initial conditions given ( s(1) =1) ):
s(1) = 1 = 3(1)^3 + 4(1)^2 - 10(1) + C
1 = 3 + 4 - 10 + C
C = 4
So, s(t) = 3t^3 + 4t^2 - 10t + 4.
Now you check which ones are true by plugging your different times in the position versus time equation s(t):
t = 0: s(0) = 4 It's true.
t = 2: s(2) = 24 It's true also.
t = 3: s(3) = 91 And again it's true!
- 1 decade ago
I assume you mean the velocity is given by v(t) = 9t^2 + 8t - 10
(missing a plus sign)
All three are true. Integrate the velocity function to get the position.
S(t) =3t^3 + 4t^2 - 10t + c
where c will equal 4 due to the initial condition given.
Then plug in for t and decide whether they are true. I assume my math was correct.