Calculus Graphing Question
Does f(x) = 2e^x / (1 x^2) have an absolute minimum value? An absolute maximum? And why? List all critical points.
I can not figure this out for the life of me... I've put it into my calculator and can see that there's no absolute max, and it looks like there's an asymptote at y = 0, but how do i say if that's an absolute min or not? And aren't critical points when the derivative = 0? Because usually that indicates a max/min, but in this case it doesn't.
- Brian DLv 51 decade agoFavorite Answer
the asymtope is horizontal ... not vertical...
vertical asymtopes create max / min....
this function is INCREASING for all values of x .. no min or max