find the equation of the tangent to the curve at the given point.

y= x-1 / x-2 at (3,2)

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  • Anonymous
    1 decade ago
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    y = (x - 1) / (x - 2)

    dy / dx = [ (x - 2) - (x - 1) ] / (x - 2)^2

    = - 1 / (x - 2)^2

    When x = 3, dy / dx = - 1.

    The tangent is:

    y - 2 = (- 1)(x - 3)

    y - 2 = 3 - x

    y = 5 - x.

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