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# find the equation of the tangent to the curve at the given point.

y= x-1 / x-2 at (3,2)

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- Anonymous1 decade agoFavorite Answer
y = (x - 1) / (x - 2)

dy / dx = [ (x - 2) - (x - 1) ] / (x - 2)^2

= - 1 / (x - 2)^2

When x = 3, dy / dx = - 1.

The tangent is:

y - 2 = (- 1)(x - 3)

y - 2 = 3 - x

y = 5 - x.

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