## Trending News

Promoted

# i need help now, i'm not good at math

can someone please help me with this problem:

Opposite corners of a small rectangular park are joined by diagonal paths, each 360 m long. What are the dimensions of the park if the paths intersect at a 65 degree angle?

### 3 Answers

Relevance

- 1 decade agoFavorite Answer
at intersection diagonals and small side form an isosceles triangle

using cosine law

a^2=b^2+c^2-2bccos(A)

where b=c= half of a diagonal =180 meters

A=65 degree

a^2=180^2+180^2-2*180^2cos(65)

=2*180^2(1-cos(65))

=37415.52

a=193.43

other side will be

=(360^2-193.43^2)1/2

=303.62

- yljacktt81Lv 51 decade ago
With x,y be dimensions, then

cos(90-(65/2))=x/360 and

sin(90-(65/2))=y/360.

So,

x=193.4279 and

y=303.6209, I THINK.

- Anonymous1 decade ago
the dimensions are 360sin32.5 degrees and 360cos32.5 degrees

or about 193.427859m and 303.62092m

Still have questions? Get your answers by asking now.