i need help now, i'm not good at math

can someone please help me with this problem:

Opposite corners of a small rectangular park are joined by diagonal paths, each 360 m long. What are the dimensions of the park if the paths intersect at a 65 degree angle?

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  • 1 decade ago
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    at intersection diagonals and small side form an isosceles triangle

    using cosine law

    a^2=b^2+c^2-2bccos(A)

    where b=c= half of a diagonal =180 meters

    A=65 degree

    a^2=180^2+180^2-2*180^2cos(65)

    =2*180^2(1-cos(65))

    =37415.52

    a=193.43

    other side will be

    =(360^2-193.43^2)1/2

    =303.62

  • 1 decade ago

    With x,y be dimensions, then

    cos(90-(65/2))=x/360 and

    sin(90-(65/2))=y/360.

    So,

    x=193.4279 and

    y=303.6209, I THINK.

  • Anonymous
    1 decade ago

    the dimensions are 360sin32.5 degrees and 360cos32.5 degrees

    or about 193.427859m and 303.62092m

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