Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 decade ago

log(2x+1) = 1 + log(x-2) ?

How would you solve this? Can you please show me the steps?

3 Answers

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  • Anonymous
    1 decade ago
    Favorite Answer

    log(2x+1)-log(x-2)=1

    log((2x+1)/(x-2))=log(e)

    2x+1=e(x-2)

    x(2-e)=-1-2e

    x=(1+2e)/(e-2)

    If u mean log is base 10 logarithm so e is 10

  • Como
    Lv 7
    1 decade ago

    Take logs as log to base 10 :-

    log (2x + 1) - log (x - 2) = 1

    log [ (2x + 1) / (x - 2) ] = 1

    (2x + 1) / (x - 2) = 10^1

    2x + 1 = 10x - 20

    21 = 8x

    x = 21/8

  • 1 decade ago

    /

    2x+1=10(x-2)

    2x+1=10x-20

    8x=21

    x=21/8

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