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Anonymous

# log(2x+1) = 1 + log(x-2) ?

How would you solve this? Can you please show me the steps?

### 3 Answers

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- Anonymous1 decade agoFavorite Answer
log(2x+1)-log(x-2)=1

log((2x+1)/(x-2))=log(e)

2x+1=e(x-2)

x(2-e)=-1-2e

x=(1+2e)/(e-2)

If u mean log is base 10 logarithm so e is 10

- ComoLv 71 decade ago
Take logs as log to base 10 :-

log (2x + 1) - log (x - 2) = 1

log [ (2x + 1) / (x - 2) ] = 1

(2x + 1) / (x - 2) = 10^1

2x + 1 = 10x - 20

21 = 8x

x = 21/8

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