Anonymous
Anonymous asked in Science & MathematicsChemistry · 1 decade ago

From the half-life for 14C decay, 5715 years, calculate the age of the shroud?

The cloth shroud from around a mummy is found to have a 14C activity of 9.5 disintegrations per minute per gram of carbon as compared with living organisms that undergo 15.2 disintegrations per minute per gram of carbon.

Question: From the half-life for 14C decay, which is 5715 years, calculate the age of the shroud.

_________________________

Please help with this problem. I have no idea where to begin.

4 Answers

Relevance
  • HPV
    Lv 7
    1 decade ago
    Favorite Answer

    You need two equations to solve this problem.

    t 1/2 = 0.693 / k and

    ln (Nt / No) = -kt . . .where Nt / No is the ratio of radioactive nuclei at time t compared to the original number of nuclei. This is proportional to the number of disintegrations at time t versus the original number of disintegrations.

    t 1/2 = 0.693 / k

    k = 0.693 / t 1/2 = 0.693 / 5715 yr = 1.21 x 10^-4 yr^-1

    ln (Nt / No) = -kt

    ln (9.5 / 15.2) = -(1.21 x 10^-4) t

    -0.47 = -1.21 x 10^-4 t

    3880 yr = t = age of shroud

    • Login to reply the answers
  • 4 years ago

    This Site Might Help You.

    RE:

    From the half-life for 14C decay, 5715 years, calculate the age of the shroud?

    The cloth shroud from around a mummy is found to have a 14C activity of 9.5 disintegrations per minute per gram of carbon as compared with living organisms that undergo 15.2 disintegrations per minute per gram of carbon.

    Question: From the half-life for 14C decay, which is 5715 years, calculate...

    Source(s): life 14c decay 5715 years calculate age shroud: https://shortly.im/lOsT0
    • Login to reply the answers
  • sovak
    Lv 4
    3 years ago

    Half Life Of 14c

    • Login to reply the answers
  • 6 years ago

    9.5/15.2=.625 or 62.5%.

    So the disintegrations are 62.5% of that of living organisms.

    .5^x=.625 ==> x=(ln.625/ln.5)= .678 half lives.

    multiply .678 half lives by 5715 (the half life of carbon 14)= 3875 or 3.9*10^3 years

    • Login to reply the answers
Still have questions? Get your answers by asking now.