# A 0.18kg ball is placed on a compressed spring on the floor. The spring exerts an average force of 2.8N?

through a distance of 15cm as it shoots the ball upward. How high will the ball travel above the release spring.

Relevance
• Anonymous

Use the law of conservation of energy in solving this problem.

Energy from spring = Energy absorbed by ball

Energy by spring = Fx

Energy absorbed by ball = mgh

where

F = force exerted by the spring = 2.8 N (given)

x = compressed distance of the spring = 15 cm = 0.15 m (given)

m = mass of the ball = 0.18 kg (given)

g = acceleration due to gravity = 9.8 m/sec^2 (constant)

h = maximum height that ball will attain after being released from the spring

Substituting appropriate values,

(2.8)(0.15) = (0.18)(9.8)h

Solving for "h",

h = (2.8)(0.15)/(0.18)(9.8)

h = 0.24 m.

• The work done on the ball = Fx will be equal to the potential energy of the ball when it reaches its maximum height h

Fx = mgh

2.8*.15=9.81*.18*h

h=(2.8*.15)/(9.81*.18)=.24m

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