a&b asked in Science & MathematicsPhysics · 1 decade ago

A 0.18kg ball is placed on a compressed spring on the floor. The spring exerts an average force of 2.8N?

through a distance of 15cm as it shoots the ball upward. How high will the ball travel above the release spring.

The answer is 0.24m. Can somebody please explain how to get this answer?

3 Answers

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  • Anonymous
    1 decade ago
    Best Answer

    Use the law of conservation of energy in solving this problem.

    Energy from spring = Energy absorbed by ball

    Energy by spring = Fx

    Energy absorbed by ball = mgh

    where

    F = force exerted by the spring = 2.8 N (given)

    x = compressed distance of the spring = 15 cm = 0.15 m (given)

    m = mass of the ball = 0.18 kg (given)

    g = acceleration due to gravity = 9.8 m/sec^2 (constant)

    h = maximum height that ball will attain after being released from the spring

    Substituting appropriate values,

    (2.8)(0.15) = (0.18)(9.8)h

    Solving for "h",

    h = (2.8)(0.15)/(0.18)(9.8)

    h = 0.24 m.

  • 1 decade ago

    The work done on the ball = Fx will be equal to the potential energy of the ball when it reaches its maximum height h

    Fx = mgh

    2.8*.15=9.81*.18*h

    h=(2.8*.15)/(9.81*.18)=.24m

  • roza
    Lv 4
    3 years ago

    l. a. Angels, i admire the Brewers, however the Halos are my team, im truly hoping for an Angels-Brewers international series this season, reason i stay in Wisconsin and identity definitely like to bypass see a series sport in Miller Park

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