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s character in bond
CH bond in benzene has a higher s character, thus has more effective overlap. The bond pairs of e- in CH bond in benzene is held closer to the nuclei.
Why higher s character, more effective overlap and e- held closer ot nuclei?
- 莫愁Lv 61 decade agoFavorite Answer
This can be explained in form of hybridization. Study the following data
For sp hybridization, s character is 50% while p character is also 50%
For sp2 hybridization, s character is 33% while p character is also 67%
For sp3 hybridization, s character is 25% while p character is also 75%
For both sp and sp2 hybridization, they have more s character comparing p
character. This implies, more electrons from s will be close(接近) to nucleus.
This is due to the penetrating effect, which indicates s orbital having a greater
chance to move towards the nucleus than that of p- and d- orbital!
In the light of a general principle, the closer the distance between the electron density (provided by s) and nucleus /nuclei, the stronger is the electron -
nuclei/nucleus attraction. And the stronger is the bond energy.
As benzene, each carbon is sp2 hybridized. This signifies each of them has a
higher s character than p. Hence the electron - nuclei/nucleus attraction is
strong. This also means their overlaps are also effective.
Give you a question to think about:
For sp3 hybridization, such as methyl group, is considered as electron
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