Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 decade ago

Absolute min and max values?

Find the absolute minimum and maximum values of y-lny on a graph with the interval (1/7, 7)

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  • 1 decade ago
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    f(y) = y - lny

    f'(y) = 1 - 1/y = (y-1)/y = 0

    y = 1

    f(1) = 1, abs min

    f(1/7) = 1/7 + ln7 = 2.089

    f(7) = 7 - ln7 = 5.054, abs max

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