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# Absolute min and max values?

Find the absolute minimum and maximum values of y-lny on a graph with the interval (1/7, 7)

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- sahsjingLv 71 decade agoFavorite Answer
f(y) = y - lny

f'(y) = 1 - 1/y = (y-1)/y = 0

y = 1

f(1) = 1, abs min

f(1/7) = 1/7 + ln7 = 2.089

f(7) = 7 - ln7 = 5.054, abs max

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