how to calculation the original concentration of Mg
An urine specimen (containing Mg) was diluted to 2L . And 10ml of aliquot was titrated with 27.32ml of 0.00396M EDTA.
Mg+ EDTA---> MgY
- CKLv 71 decade agoFavorite Answer
no. of mole of EDTA = (27.32/1000)x0.00396 = 1.08187X10^-5
no. of mole of Mg2+ = 1.08187X10^-5
no. of mole of Mg2+ in the 2L sample = 1.08187X10^-5 X (2000/10)
Conc. = 2.13X10^-3 / 2 = 1.082X10^-3 M