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# How to answer using the sum of two cubes?

the equation:

64y^6+1

and can you please not tease me for being stupid? im only 14.

Update:

and can you tell me how you did it?

i'll make your answer best answer right away.

i promise.

### 1 Answer

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- Anonymous1 decade agoFavorite Answer
1 is the cube of 1, as 1 * 1 * 1 = 1.

64y^6 is the cube of 4y^2, as (4y^2)(4y^2)(4y^2) = 64y^6.

Therefore, written as the sum of two cubes, 64y^6 + 1 is:

(4y^2)^3 + 1^3.

An equation needs to have two sides to it.

As written, 64y^6 + 1 isn't an equation.

However, if it is equal to something, such as 0, then it becomes an equation.

64y^6 + 1 = 0 is an equation.

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