How to answer using the sum of two cubes?
and can you please not tease me for being stupid? im only 14.
and can you tell me how you did it?
i'll make your answer best answer right away.
- Anonymous1 decade agoFavorite Answer
1 is the cube of 1, as 1 * 1 * 1 = 1.
64y^6 is the cube of 4y^2, as (4y^2)(4y^2)(4y^2) = 64y^6.
Therefore, written as the sum of two cubes, 64y^6 + 1 is:
(4y^2)^3 + 1^3.
An equation needs to have two sides to it.
As written, 64y^6 + 1 isn't an equation.
However, if it is equal to something, such as 0, then it becomes an equation.
64y^6 + 1 = 0 is an equation.