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Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 decade ago

can you help me what is deviation of a equilateral triangular prism of 5 cm taking 35 degrees as the ray?

please very important for my praticals

1 Answer

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  • MaX
    Lv 5
    1 decade ago
    Favorite Answer

    To solve this you must know the index of refraction, n.

    If the prism use crown glass, n ≈ 1.52

    If the prism use SF10 Crystal, n = 1.72803

    α = 90° - 35° = 55°

    A = 60°

    Angle deviation,

    ε = α - A + arcsin[sin(A) * sqrt[n^2-(sin(α))^2] - cos(A)*sin(α)]

    If n = 1.52,

    ε = [55 - 60 + (180/pi) * (arcsin( sin(60*pi/180) * (1.52^2 - ( sin(55*pi/180) )^2 )^0.5 - cos(60*pi/180) * sin(55*pi/180) ))]°

    ε ≈ 39.369°

    If n = 1.72803,

    ε = [55 - 60 + (180/pi) * (arcsin( sin(60*pi/180) * (1.72803^2 - ( sin(55*pi/180) )^2 )^0.5 - cos(60*pi/180) * sin(55*pi/180) ))]°

    ε ≈ 60.246°

    For more info, go to source...

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