How do you solve this algebra expression problem?

Ok I dont understand how to solve this problem

2xyz+5

if

x=2

y=3

z=4

I dont understand how you multiply all that variables at once

could some one please explain to me how to answer this problem

It is quite difficult for me because I skipped pre-algebra and do not quite remember how to solve these types of problems

11 Answers

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  • Pranil
    Lv 7
    1 decade ago
    Favorite Answer

    2xyz+5

    2xyz + 5

    = (2 × x × y × z)+(5) ---------- substitute values of x, y and z

    = (2 × 2 × 3 × 4) + 5

    = 48 + 5

    = 53

    ----------

  • 1 decade ago

    When there is no sign between numbers/variables, that implies multiplication. So your equation could be written 2*x*y*z+5. You know the values of the variables, so you just substitute those values for the corresponding letter. The equation now looks like: 2*2*3*4+5

    You perform multiplication before addition and you can do the multiplication steps one at a time. 2*2=4, so that answer times the next number. 4*3=12, then that answer times the next 12*4=48, and then complete the addition, 48+5=53.

    Source(s): me
  • 1 decade ago

    Well first you plug in all the numbers:

    2(2)(3)(4)+5,

    then you multiply first: 2*2=4*3=12*4=48

    Once you get that which equals 48 in this case, then you add the 5 which is going to come out to be 53.

    But remember you have to multiply first then add. O.K.

  • 1 decade ago

    It helps if you put each term in brackets

    So instead of

    2xyz+5

    You can have

    (2)(x)(y)(z)+(5)

    We can now sub the numbers in you've already got, thus giving us

    (2)(2)(3)(4)+5

    If terms are next to each other with no sign it means to multiply them.

    You don't need to do all the multipications at once either.

    For example you could do:

    ((2)(2))((3)(4))+5

    or

    (2*2)(3*4)+5

    this simplifies down to

    (4)(12)+5

    which then again simplifies to

    (48)+5

    which finally equals

    53.

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  • Anonymous
    1 decade ago

    2xyz+ 5

    subbing in the values of xyandz

    2 X 2 X 3 X 4 + 5

    just multiply them one at a time

    4X 3 X 4 +5

    12 X 4 +5

    48+ 5

    53

    remember PEMDAS?? parenthesis exponents multiplication addition then subtraction thats the order to go in

  • 1 decade ago

    Replace each variable by its value:

    2(2)(3)(4) + 5

    Multiply: 2*2*3*4 = 4*3*4 = 12*4 =48

    48 + 5

    53

  • 1 decade ago

    the answer is 53. you want to multiply 2 times 2, 3, and 4 then take that answer then add 5 to that.

  • 1 decade ago

    the thing is wen there is a problem like that its mostly multiplication so just do 2x2x3x4=48 and then add the 5= 53

  • 1 decade ago

    2x2=4

    4x3=12 etc. you just multiply 2 and the multiply the answer times the next #

  • 1 decade ago

    it does not matter in which order you multiply them!

    2(2)(3)(4)+5

    it is saying 2x2x3x4+5

    you just need to do the short math it is nice and easy!

    53

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