Anonymous
Anonymous asked in Science & MathematicsChemistry · 1 decade ago

What is the correct chemical equation for vinegar and baking soda?

I am trying to put lesson plans together for a basic, introductory chemistry class I am teaching this summer. On the internet, I have found 2 different chemical equations for the vinegar/baking soda reaction.

Equation 1:

CH3COOH + NaHCO3 ---> CH3COONa + H2O + CO2

Equation 2:

NaHCO3 + HC2H3O2 [YIELDS] NaC2H3O2 + H2O + CO2

Which one is right? Why is it right?

5 Answers

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  • lo
    Lv 6
    1 decade ago
    Favorite Answer

    Equation 1 is right.

    Equation 2 accounts for the same number of atoms, but it's written in the wrong sequence. For example, the product in Equation1 correctly indicates that the Na ion is located next to the oxygen atom (not the carbon atom as incorrectly indicated in Equation 2).

    Reading the first replier's answer, maybe both are technically correct. But Equation 1 is better and preferred, since it shows how the atoms are arranged in the molecule.

  • Anonymous
    1 decade ago

    Write out the equation into a structural chemical formula (it would be tons easier if you write it down as I describe it).

    Equation 1 is correct and this is how the reactants form the products:

    Write down 2 carbons (C) with a single bond between them. On the left C use the other 3 bonds C has available for H's - 1 coming off the top, one to the left side and 1 on the bottom. On the right C one bond it taken up with the bond to the left hand carbon. That leaves 3 empty bonds. To the left, use bonds 2 & 3 to form a double bond with one of the O's. Use bond 4 to connect with an OH. You have just written out the chemical formula for acetic acid (vinegar)

    Baking soda: NaHCO3. Write 1 C. To the left use one of it's 4 bonds to add a H and add a Na to the left of the H (there was an extra space because the H has to be H+). Back to the C, add 3 H's - one on top, one to the right and one on the bottom.

    Products: Take the H from the baking soda, one of the O's and the H from the OH on the vinegar to make H2O (water). Now from the baking soda take the C and two remaining O's to form CO2 (carbon dioxide). That leaves Na from the baking soda. The acetic acid has lost only one H from the OH so far. On the right hand carbon, keep the single bond with the one O intact. Break the double bond with the other O. Keep one bond with that O and give the free one to Na. Reading left to right you have CH3COONa, sodium acetate.

    (In equation 2, the baking soda is written correctly but the although the chemical formula could be written down the same as in equation 1, as it is written down structurally, isn't in the correct order to form acetic acid)

  • ?
    Lv 7
    1 decade ago

    There's nothing wrong with either of them but, the first one is the generally accepted form of the equation.

    Because 'O' Must have 2 bonds and 'C' Must have 4 bonds, the structure Must look as below, otherwise, as a straight chain, the 1st 'O' couldn't have 2 bonds nor the 2nd 'C' 4 bonds.

    CH3-C-O-H.

    ........||

    ........O

    Equation 1:

    CH3COOH + NaHCO3 ===> CH3COONa + H2O + CO2

    '===>' means 'Yields'.

    Equation 2:

    NaHCO3 + HC2H3O2 [YIELDS] NaC2H3O2 + H2O + CO2

    ('HC2H3O2' is a rather convoluted form of the formula for acetic acid)..

  • 1 decade ago

    if you look carefully equation 1 and 2 are the same ...NaHCO3 + CH3COOH ( = HC2H3O2) and the sodium salts are the same...I prefer the top equation it makes it easier to follow the reaction but technically both are correct.

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  • Anonymous
    5 years ago

    For the best answers, search on this site https://shorturl.im/aydQP

    Acetic acid can be written as CH3COOH or HC2H3O2 (the same as your C2H4O2). Just remember that H2CO3 decomposes to give CO2 and H2O.

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