Anonymous
Anonymous asked in 科學及數學化學 · 1 decade ago

pH Calculation

Assume a strong acid solution at pH12 be diluted into 2% by DI water, what is the pH of the resulting solution?

Update:

It should be "strong alkali" instead of strong acid.

1 Answer

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  • 1 decade ago
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    Consider the original alkali:

    pH = 12

    pOH = 14 - pH = 14 - 12 = 2

    [OH-] = 10-pOH = 10-2 = 0.01 M

    Consider the diluted solution:

    It is diluted into 2%.

    [OH-] = 0.01 x 2% = 0.0002 M

    pOH = -log[OH-] = -log(0.0002) = 3.7

    pH = 14 - pOH = 14 - 3.7 = 10.3

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