The combustion of ammonia in the presence of excess oxygen yields NO2 and H2O:?
4 NH3 (g) + 7 O2 (g) → 4 NO2 (g) + 6 H2O (g)
The combustion of 43.9 g of ammonia produces ________ g of NO2.
- 1 decade agoFavorite Answer
4 moles of NH3 give 4 moles of NO2
so 1mole of NH3 will give 1 mole of NO2
43.9 grams of NH3 contains 2.58 moles
so 2.58 moles will be produced of NO2
which is 118.7 grams
u can find the number of moles by dividing the mass with relative molecular mass
and can find the mass by multiplying no of moles with relative molecular mass