Probability question - 10 points to first person who answers correctly!?
Susan has red, blue, green & yellow sweaters.Joanne has green, red, purple & white sweaters. Diane's sweaters are red, blue, purple and mauve. Each girl has only one sweater of each color and will pick a sweater at random. Find each probability:
1. P(each girl choses a different color)
2. P(each girl chooses the same color)
3. P(2 girls chose the same and 3rd chooses different color.)
4. P(each girld chooses a red sweater)/ Is this 1/64 and how is this question different than 2?
- 1 decade agoFavorite Answer
1) 32/64 = 1/2 different color.
8+8+8+8 =32 ( for example for red : RGB, RGP, RGM, RPB, RPM, RWB, RWP, RWM )
total : 64
2) there is only red color that all three girls have.
1/ 64 ( or you can think as 1/4*1/4*1/4)
3) tricky because of the red color.
2 girl same with blue is 4, green is 4, purple is 4
but red is total : 9
9 + 12 = 21
4) yes it is 1/64 . It is different than 2 because as I told you red color is the trick here. The answer change because of the red color... Red color 1/3 for each different person.
- 1 decade ago
I don't know if these answers are correct. I'll still give them to u anyway. 1.) I think that it's 9 1/12. 2.)I think the answer is 3/12, which = 1/4. #3.) I think the answer is 1/2. I'm sorry, but I don't know the answer to number 4.