Calculate the pH of a strong acid solution of 0.080 M HCl. Express your answer to the nearest 0.1 pH unit.?
Calculate the pH of a strong acid solution of 0.080 M HCl. Express your answer to the nearest 0.1 pH unit.
- MateoLv 41 decade agoFavorite Answer
since HCl is a strong acid, it completely dissociates so
[H+] = [Cl-] = 0.08 M
pH = -log(H+)
pH = - log(0.08)
pH = 1.1
- louellaLv 44 years ago
To find the PH of a strong acid you get it's molarity, this case it is .0001M and take the -log of it. SO this means that the -log(.0001) is equal to 4. so it has a PH of 4. Also, Sulfuric acid (H2SO4) is considered a strong acid, which means it dissociates in water 100% where as citric acid dissociates in water <100%. In other words there are more electrolytes when you have a strong acid rather than a weak acid. (electrolytes are free ions that conduct electricity in water) Not really sure if I explained it very well, sry.