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# 文字題 一元一次不等式 幫幫我呀 thx 10分

已知3乘以x加上4小於－11,求x值的可能範圍.

若兩個連續奇數的和不大於80,求當中較小的數的最大可能值.

若兩個連續偶數的和不小於36,求當中較大的數的最小可能值.

已知何先生有$300,他打算購買6張戲和數罐票汽水.若每張戲票和每罐汽水的售價分別是$45和$6,問何先生最多能買多少汽水?

要步驟 thx thx

### 3 Answers

- Anonymous1 decade agoFavorite Answer
plus minus times divided by equals

1.

x times 3 plus 4 smaller or equals to 11

x times3 smaller or equals to -15

x smaller or equals to -5

2.

Suppose the two continuous odd numbers are x and x plus 2.

x plus (x plus 2) smaller or equals to 80

x times 2 plus 2 smaller or equals to 80

x plus 1 smaller or equals to 40

x smaller or equals to 39

So the smaller one smaller or equals to 39.

3.

Suppose the two continuous even numbers are x minus 2 and x.

(x minus 2) plus x larger or equals to 36

x times 2 minus 2 larger or equals to 36

x minus 1 larger or equals to18

x larger or equals 19

But because of x is even numbers ,so x larger or equals 20

4.

Suppose a can coca cola's amount is a.

6 times 45 plus 6a smaller or equals to 300

270 plus 6a smaller or equals to 300

6a smaller or equals to 30

a smaller or equals to 5

So he can buy 5 can coca cola at most.

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- shingoLv 61 decade ago
1.

3x+4<-11

3x<-11-4

3x<-15

x<-5

ans:x<5

2.

兩奇數係x同x+2

x+x+2<80

2x+2<80

2x<78

因為x<39

x=37

ans:37

3.

兩偶數係x同x+2

x+x+2>36

2x+2>36

2x>34

x>17

x=18

ans:18

4.

300-45x6=30

30/6=5

ans:5

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- 1 decade ago
已知3乘以x加上4小於－11,求x值的可能範

3x+4<-11

3x+4-4<-11-4

3x<-15

x<-5

可能範圍.x<-5

若兩個連續奇數的和不大於80,求當中較小的數的最大可能值.

.(x+1)(x+3)<80

x^2+x+3x+3<80

x^2+4x-77<0

(x+11)(x-7)<0

x+11<0 or x-7<0

x<-11(rej) or x<7

最大可能值x<7

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